int (ln(ax) dx) The integral of ln(ax)
u=ln(ax) dv=dx Set U equal to ln(ax) and dv equal to dx
du= (a/x) dx v=x Derive u and integrate dv to get du and v
int (ln(ax) dx) = uv - int (v du) Equation for integration by parts
int (ln(ax) dx) = (ln(ax)) * x - int( x * (a/x) dx) Sub u, v and du into the equation
==x * ln(ax) - x + C Solve