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seriously. explain it then instead of being a dick.
your sixth grade teacher will probably tell you that opposite charges exert an attractive force on each other. However as we are dealing with electrically neutral molecules. So why is there an attractive force here?
you can't just say "polarization". I can memorize a bunch of fancy words as well, but it doesn't mean I understand what is going on.
this video can't be correct though, because we know that the charges are not free to move across the width of the water stream, which is many many molecules thick. They charges are bound to the water molecules. This is not free charge like in a metal.
I don't really see where you're coming from. Are you trying to say that nobody knows why the water is attracted?
If my sixth grade teacher told me that she wouldn't be wrong. There is an electrical attraction between the comb and the water. The H2O molecules may be electrically neutral but the individual atoms aren't; Hydrogen is slightly poisitve and the Oxygen slightly negative. This results in polarization (do you need me to define this term too?) of the H2O molecule and thus becomes attracted or repelled to charged objects.
I feel like your whole post is just bait trying to get me to say something wrong so please enlighten me
no I agree with you up to this point. I just don't like how you jump from polarization to saying that they will repel or attract charged objects.
why does this happen?
The original guy took something that is very cool, and makes people think about physics, and was just like "what are you in 8th grade?", as if this was a phenomenon that is ridiculously simple to explain. You did the same thing. Telling me that I should consult a 6th grade teacher.
yet no one has explained to me yet why the polar molecules will be attracted to the comb. Saying "because they are polar" is not a good explanation. It's just something that people have told you. I don't need you to define what a polar molecule is, but I do want you to tell me why there is an attractive force between the water molecules and the comb.
You're acting like electric attraction isn't a thing. I get what you're getting at and I like how you encourage questioning rather than accepting but it doesn't really work here. It really is as simple as "opposite charges attract".
Are you looking for an explanation as to why opposite charges attract? That would be a great question that I cannot answer.
Don't really follow. If you simplify the water molecule into a line, there will be a higher concentration of electrons on one side than the other if you bring a charged object near it. Sorry but I don't understand your question
Well, they don't cancel each other out, but they inversely effect each other.
Honestly, I really don't know. I'm interested in quantum physics and whatnot, but I don't really have half a clue when it comes to any of it. I also can't find one same answer in a quick google, soo...
There's actually an uneven distribution of electrons regardless of what's near it. Water's shaped like an L, with hydrogen atoms on each of the ends, and the oxygen at the bend. Oxygen is more electronegative than Hydrogen, meaning it pulls on the electrons more. Because of this, the electrons spend more time around the oxygen meaning the oxygen-side has a more negative charge, and the hydrogen-side has a more positive charge
yeah. I guess we can simplify the water molecule into a dipole. Also at the scales we are dealing with, we can assume that the electric field of the comb is more or less homogenous in the region of the dipoles, and the dipoles are pure dipoles (the comb is really wide, the distance to the stream is small, and the molecules are very tiny.
Thus there should be no net force on the dipoles right?
we can assume that the electric field of the comb is more or less homogenous in the region of the dipoles.
Yes
the dipoles are pure dipoles (the comb is really wide, the distance to the stream is small, and the molecules are very tiny.
Eh... Pure dipoles? Don't think we can assume that here. What are you implying with these size classifications
Thus there should be no net force on the dipoles right?
Why?
As long as the water molecules' charges can move at all and the comb is charged, there will be an attractive electric force between the comb and the water.