Replying to .999...=/=infinity

.999... is not a number. It is a limit as the variable approaches infinity [lim(n->infinity)(1-1/n)]. Infinity does not exist. Therefore, .999... does not exist. It exists in theory because we treat infinity as a number. That's fine, because it works. However, when we treat infinity as a number in theoretical applications such as limits, derivation, and integration, we have to remember that we are treating infinity as a number, and can therefore manipulate it as a number with operations such as subtraction and addition. That means we can take a hypothetical number n=1-[1/(infinity-1)], which is equal to .999.... If .999...=1, then 1-[1/(infinity-1)]=1, which means 1/(infinity-1)=0, which means 1=0(infinity-1). This is clearly incorrect, since 0x, with x being a number, is always equal to 0, and infinity is being treated as a number in this situation. Of course infinity is not a number and cannot be manipulated like this in real life, but infinity doesn't exist, so using infinity in limits also doesn't work in real life. It only works in theory when infinity is treated as a number. Claiming that .999...=1 is allowing infinity to be manipulated as a number in some ways that do not work in real life but not in others, all within the same theoretical situation. The difference between .999... and 1 is negligable to the extent that they can be treated as the same number in practical applications, but they are, by definition, not equal.