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I did look at those, but there are still a few problems. The bigest being that unless you happen to be a podetrist, how can you possibly know how you want to mold it to properly support your foot.
Its not as simple as just filling the gap under the medial and lateral archs, its making sure that the archs are properly supported in a neutral stance when under load.
Thats the second problem, these insoles are made for skaters. The forces they put through there feet are not even close to that which skiers feet are under. Take for example a 30Mph corner on skis. The G force in that corner will put twice your body weight through your feet, so the footbed needs to be stiff enough to resist this. Now thats only 30Mph, as you ski faster this only increases. Skaters dont even get close to those kinds of speeds. Yes they have sudden hard impacts, but its not a sustained load like a turn in skiing.
Im sure they are great footbeds for there intended use of skating, but they certainly will not be as good as a well made skiing footbed, made by a profesional fitter.
Uh, a skier of mass ~80kg travelling at 30mph in a turn of 10m radius will experience roughly 2G of centripetal force, give or take a coupla hundred newtons.
Juuuuuust saying.
G-force (or Gs) is just the equivalent force of gravity on an object.
Force = Mass x Accelleration - The accelleration from gravity is a constant (9.81m/s although a lot of times you just use 10) so you multiply the mass (say 80kg) by 10 to get 1G for that person - so in this instance, 1G = 800 Newtons (N) of force.
In a turn, you're comparing the centripetal force (the force towards the centre of the arc, which is what lets you turn) to the equivalent gravity.
The equation for centripetal force equals (Mass x Velocity squared) divided by the radius
So if you're going 30mph ~= 13.4m/s, you weigh 80kg and you're going around a turn of radius 10 metres:
F = mv^2/R
F = 80 * (13.4*13.4) / 10
F = 1436.48 Newtons
The force of 1G on an 80kg rider is 800N so 1436N isn't that far off double that, AKA 2G
I mean we could work out all the crap like frictional losses and do vector diagrams but for the sake of the argument I thought this was sufficient:
Spark notes: Herp derp, algebraic.
