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hi_vis360
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PLEASE factor this for me!

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1440ski
Posts: 2049 - Karma: 1,110
This is for a quiz if anybody could factor this that would be a great help. Thanks! +kkkk

Factor (x-5)(x^2+x+2)
May 9 2012 11:48PM
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Jakx~
Posts: 653 - Karma: 503
I hate my math addiction, yeah here one sec

May 9 2012 11:53PM
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Darth.Maul
Posts: 2472 - Karma: 652
The first term is already factored so you could just factor an x out of the 2nd part which would give youe x(x-5)(x+2)
May 9 2012 11:54PM
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1440ski
Posts: 2049 - Karma: 1,110
Thanks man
May 9 2012 11:54PM
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Jakx~
Posts: 653 - Karma: 503
It's a non real answer, want an explanation?
May 9 2012 11:55PM
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Darth.Maul
Posts: 2472 - Karma: 652
wait fuck me i thought it was (x^2+2x) forget what i said you can't factor an x out because theres a 2 in there
May 9 2012 11:55PM
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Rafiki
Posts: 3858 - Karma: 2,251
i got x^3-4x^2-3x-10
i think that's right...
May 9 2012 11:56PM
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thatsG
Posts: 2571 - Karma: 1,789
wolframalpha.com


May 9 2012 11:56PM
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Rafiki
Posts: 3858 - Karma: 2,251
oh wait that's mulitplying it out nevermind
May 9 2012 11:56PM
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.MintBerryCrunch
Posts: 750 - Karma: 346
-10 + -3x + -4x2 + x3
May 9 2012 11:57PM
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1440ski
Posts: 2049 - Karma: 1,110
Thanks everyone figured it out like
May 9 2012 11:59PM
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gotti
Posts: 4269 - Karma: 4,550
this thread is full of fail.

and that kid is right you can't factor it. if you plug it into a calculator, there is only one root, so you can't possibly factor it more. I tried reducing by using 5 as a root and came out with an imaginary number.


Unfortunately there are no asians on ns.
May 9 2012 11:59PM
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Darth.Maul
Posts: 2472 - Karma: 652
He said factor, not multiply them together.

If your looking for answers, depending on the context of the question, you could solve (x-5) and (x^2+2+2) separately for 0 which would give you 5 and a nonreal answer since you get 1 +- root(1-8) / 2
So it would be 1+-i(7^1/2)/2
May 10 2012 12:00AM
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Darth.Maul
Posts: 2472 - Karma: 652
I used the quadratic equation in case you were wondering. And if you don't know i = square root of -1 which is an imaginary number
May 10 2012 12:01AM
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whoa-dere
Posts: 10596 - Karma: 7,105
im asain ;)
May 10 2012 12:02AM
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gotti
Posts: 4269 - Karma: 4,550
can you please inform me of how you factored it?
May 10 2012 12:02AM
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why
Posts: 2064 - Karma: 65
this reminded me why I have a D in math.
May 10 2012 12:02AM
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Rafiki
Posts: 3858 - Karma: 2,251
herrr derrr look what i posted after
May 10 2012 12:04AM
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Darth.Maul
Posts: 2472 - Karma: 652
ya its cool i fucked up at first too!
May 10 2012 12:05AM
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NinetyFour
Posts: 8650 - Karma: 13,411
Ok wouldn't the first half be x=5 and then you would plug in the x^2+x+2 into the quadratic formula , then set those factors equal to zero and solve. Then check for extraneous roots? That's how we do it at school I think.
May 10 2012 12:10AM
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Darth.Maul
Posts: 2472 - Karma: 652
Ya and that gives you 1+- i(7^1/2) / 2
May 10 2012 12:15AM
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crieschl
Posts: 644 - Karma: 108
The first term would make x=-5, and the other one you have to use the quadratic formula to figure it out, which then would be your second term, and if you completely simplified it, it would be an imaginary number. but if you haven't learned about them yet, I would just write it out like I have it (while taking into account that I'm typing it out, so it looks a little weird haha)

x= 5, (-1±√(-7))/2
May 10 2012 12:18AM
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NinetyFour
Posts: 8650 - Karma: 13,411
Oh, I didn't even realize you did it already! Thanks :)
May 10 2012 12:18AM
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crieschl
Posts: 644 - Karma: 108
5, not -5
May 10 2012 12:19AM
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JIBpsy^^
Posts: 2851 - Karma: 36
You gotta plug that shit into the quadratic. Google it and do it yourself
May 10 2012 12:20AM
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