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College pre calc help, i hate takehome tests

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Gmart
Posts: 1634 - Karma: 273
question is, with the given zeros find the fifth degree equation,

-2i, √3, 1 (negative 2 eye, square root of three, and one)

+k for serious answers
Mar 18 2012 9:15PM
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Timmy.
Posts: 507 - Karma: 22
id help but i forget it all, you might need to know that another zero is positive 2i
Mar 18 2012 9:17PM
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jibjim
Posts: 1814 - Karma: 10
the zeroes are the roots of the equation, or the numbers you find when the equation is factored

(x^2+2)(x^2-3)(x-1)

i don't know if the teacher wants factored form, or standard form. If they want standard form, just multiply that out so it looks like:

ax^5+bx^4+cx^3+dx^2+ex+f=0

Mar 18 2012 9:18PM
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Gmart
Posts: 1634 - Karma: 273
thanks for trying, still don't get it tho, i've been struggling with this course since the beginning of the semester  +k tho
Mar 18 2012 9:20PM
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406
Posts: 2302 - Karma: 92
by zeros i assume you mean roots so... (r-1)(r - sqrt3) then you cant just have a -2i....it should be like 0 plus/minus 2i (real and imaginary part)

but even with those 4 roots its would be a 4th degree polynomial, unless zero is a root where r (in this case) could be factored out of the equation
Mar 18 2012 9:22PM
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Timmy.
Posts: 507 - Karma: 22
this op i remember now hes got it exactly
Mar 18 2012 9:24PM
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Gmart
Posts: 1634 - Karma: 273
ok i get it to an extent, so i get the x^2 - 3, that gives u √3, and x-1 gives you 1, but, how do you get the negative 2i, is √-2 = to 2i?
Mar 18 2012 9:28PM
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navierSTOKED
Posts: 858 - Karma: 33
yes.
Mar 18 2012 9:32PM
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1337
Posts: 31053 - Karma: 29,231
i love take home tests, bastard. Lrn2wolfram alpha
Mar 18 2012 9:36PM
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Andreas_
Posts: 210 - Karma: 21
This!
Mar 18 2012 9:38PM
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Gmart
Posts: 1634 - Karma: 273
sorry, i'd rather ask a question and learn then hand in something with no answer.  and what? lrn2wolfram alpha, learn to work from a lpha? no entiendo
Mar 18 2012 9:41PM
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Ute
Posts: 9 - Karma: 10
wolframalpha.com is an amazing tool.
Mar 18 2012 10:31PM
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AlwaysDisagrees
Posts: 248 - Karma: 45
This is a really weird question. If -2i is a zero, then +2i also has to be a zero. Also, in order to make it a fifth order polynomial, you're going to have to have a double root. How are you supposed to choose between 1, and root3 as your double root?
Mar 29 2012 8:01PM
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