Heat Lost by Water = Heat Gained by Pt
mass of water x dT of water x sp.ht. of water = mass of Pt x dT of Pt x sp.ht. of Pt
Let SH = sp.ht. of Pt, then sp.ht. water = 32SH
100 g x dT(w) x 32SH = 100 g x dT(Pt) x SH
dT(w) x 32SH = dT(Pt) x SH
Let s = final T of water and Pt; dTw = 100 - s and dT(Pt) = x - 0
(100 - s) x 32SH = (s - 0) x SH
3200 - 32 s = s
33 s = 3200
s = 97 C
Pt goes from 0 to 97 C; Water goes from 100 C to 97 C
Seem right?