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Extra credit homework help.

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Wes-Side
Posts: 200 - Karma: 10
So I know there are some pretty smart people on here (and even more dumbasses). Anyways my math teacher recently assigned an extra credit problem I was looking to get some help from people on here. If you do understand how to do this problem, I am not just looking for an easy answer, I would like to understand the steps used to get to that answer.

Anyways here is the question.

There are four large groups of people, each with 1000 members. Any two of these groups have 100 members in common. Any three of these groups have 10 members in common. Ad there is one person in all four groups. all together how many people are in these four groups
Apr 5 2011 5:47PM
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[evan]
Posts: 5628 - Karma: 117
There's four groups with 1000 members each. How many people are there all together? Well unless I'm missing some major detail here it seems like the answer is 4000 people.
Apr 5 2011 5:55PM
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Mr.Turtle
Posts: 3690 - Karma: 96
thats what i thought also but i feel like theres something else
Apr 5 2011 5:56PM
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yeahno
Posts: 4008 - Karma: 3,414
4000 dumbass
Apr 5 2011 5:56PM
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Wes-Side
Posts: 200 - Karma: 10
There ARE 4000 members but what you have to remember is that since people are in multiple groups it is not possible that the answer is 4000 people.
Apr 5 2011 5:58PM
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240sxKid
Posts: 733 - Karma: 3
he probably means common people, which would be 234
Apr 5 2011 5:58PM
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Wes-Side
Posts: 200 - Karma: 10
What do you mean by common people? I'm pretty sure that the answer isn't 234....
Apr 5 2011 6:00PM
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240sxKid
Posts: 733 - Karma: 3
Ohhhhh, 3797 i think.
Apr 5 2011 6:00PM
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CAPITA-DEVOURS
Posts: 1968 - Karma: 4
if he wanted to know that there was 234 people in common, he would have to be more specific. it is most likely asking for the total of all the people combined being 4000, trying to confuse you ahah
Apr 5 2011 6:01PM
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240sxKid
Posts: 733 - Karma: 3
and ask if you need it worked out. i was lazy
Apr 5 2011 6:01PM
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[evan]
Posts: 5628 - Karma: 117
I'm pretty sure you have the math skills of an elementary school student.
Apr 5 2011 6:01PM
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240sxKid
Posts: 733 - Karma: 3
You mean me? haha
Apr 5 2011 6:02PM
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[evan]
Posts: 5628 - Karma: 117
Actually nevermind, I probably mis-understood the question. Don't listen to me, I'm too tired for math.
Apr 5 2011 6:03PM
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Wes-Side
Posts: 200 - Karma: 10
haha lol. Don't be so harsh on them. I wish it was that easy. To everybody who thinks the answer is in the wording let me assure, it is a serious math problem.
Apr 5 2011 6:03PM
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240sxKid
Posts: 733 - Karma: 3
Yeah, but the 4 groups can have interchangeable people. I dunno, too hard to explain, but i think i got it right. Im pretty good at math and logic and shit or whatever this is.
Apr 5 2011 6:04PM
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240sxKid
Posts: 733 - Karma: 3
3797! AMIRITE?
Apr 5 2011 6:05PM
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Wes-Side
Posts: 200 - Karma: 10
Could you work that out? Just to make sure everything is kosher before I go and try to explain the answer to my teacher.
Apr 5 2011 6:06PM
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240sxKid
Posts: 733 - Karma: 3
its easier with a picture but ill try. So four groups, 2 have 100 in common, 3 have 10 in common, and 4 have 1 in common. So lets go backwards. subtract everything from 4000. 4 people(the four groups with these in common), 26(3 groups X 10 people = 30 - 4 because we already counted them), then 174(because 200 - 27) and that should equal 3797 if i did the math right, i always make stupid mistakes. lemmy do it again,

NOOO WAIT ITS 3796. THERE. Correct if wrong
Apr 5 2011 6:11PM
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Wes-Side
Posts: 200 - Karma: 10
I think you are right as when I first started this problem I took almost an identical course to figuring it out but for some reason I had a nagging doubt in the back of my mind that i had to be wrong somehow. Could everyone else now just look at the logic behind this and see if we are missing anything?
Apr 5 2011 6:18PM
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fourhundred
Posts: 2760 - Karma: 21
we worked on problems like this in my data managment class, something to do with venn diagrams

Apr 5 2011 6:23PM
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BIGben*
Posts: 1942 - Karma: 8
So 4000 people and ther 1 in common for all. 4000- ( 4+30+200) = your anser i dont have a calculator So the 4 is beacause ther is one guy in all four groups the 30 beacause 10x3 And the 200 is the 100 common people x 2
Apr 5 2011 7:45PM
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Saac
Posts: 767 - Karma: 333
you are one of the many dumb asses
Apr 5 2011 7:52PM
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S.C
Posts: 3068 - Karma: 2,285
3,889?? i didnt read the other posts tho
Apr 5 2011 7:55PM
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Yeezus
Posts: 3350 - Karma: 469
3769

100 x 2 = 200
10 x 3 = 30
+ 1
=
231

now
4000 - 231 = 3769
Apr 5 2011 8:13PM
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240sxKid
Posts: 733 - Karma: 3
Its a trick question, the person didnt specify if the common people are also common in the 10 people in 3 groups and the 100 people in 2 groups.
Apr 5 2011 8:47PM
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