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Late night circuits help??

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Gnarshred
Posts: 5670 - Karma: 18
so i'm retarded, and didn't realize I had homework due tomorrow and now its 11 pm, Im still hung over, and have no idea what I am doing. Any help would be appreciated:

A new 1.5 V AA Battery delivers 40 kJ of energy during its lifetime. How long will the battery last in an application that draws 10 mA continuously? Assume the battery voltage remains constant.

I know its a long shot, posting it here, but I know there are a ton of EE's on here, so its worth a shot! thanks

Gnarshred
Aug 30 2010 1:17AM
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Arabian.
Posts: 9632 - Karma: 55
Can you not do basic algebra?
Aug 30 2010 1:21AM
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Bukkakeskitrip
Posts: 5677 - Karma: 95
740.741 hrs
Aug 30 2010 1:24AM
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Gnarshred
Posts: 5670 - Karma: 18
I can if I could figure out what equation relates those values. Care to help? You can give me all the shit you want, I just want some help.
Aug 30 2010 1:27AM
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Bukkakeskitrip
Posts: 5677 - Karma: 95
or do you need the equation aswell?
Aug 30 2010 1:27AM
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Gnarshred
Posts: 5670 - Karma: 18
That'd be fantastic. I don't even really need work shown, I'll figure it out myself, my notes are just all jumbled from the week, haven't really gotten my ass in gear for school yet.
Aug 30 2010 1:29AM
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Bukkakeskitrip
Posts: 5677 - Karma: 95
1.5[V] * 0.010[A] = 0.015[W], but[W] = [J]/[s], so
40,000[J]/0.015[J]/[s] = 2,666,666.66 [s](seconds)

2,666,666.66 seconds = 740.741 hours
Aug 30 2010 1:29AM
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Gnarshred
Posts: 5670 - Karma: 18
Perfect thanks KimJong, I don't care what they say, you're my favorite dictator.

+k for you!
Aug 30 2010 1:37AM
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