i got a problem in maths so please help me
2x + 3 4x+7
-------- + ------- = 7
2x-3 2x-4
another one:
x(x-5) -3 = (2x-1)² -4
please show me the whole way
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2nd problem is x=0, x=-1/3 get those answers by completing the square and gettin one side equal to 0 (so that you can derive x using the quadratic formula). the -4ac will cancel because there is no c value in your equation you'll plug in, so dont worry about your equation looking funny
the first one i dont really feel like doin but get a common denominator and bring the 7 to the other side if you want to use the quadratic formula to solve for x because one side has to be equal to zero for the quadratic formula to work