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  • Diff eq help
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Replying to Diff eq help

TeamJones:
This may be the wrong place to put it, but I'm having some problems:

Start with 200000 mosquitoes in a population which doubles every week. Predators eat 20000 mosquitoes a day. Model the population at any given time.

So... start with
dP/dt=2P-140000
P is population, t is in weeks.
Seperation of variables gives me (after everything) something like P=70000+130000e^2t. The solution in the book is P=140000/ln2-ce^(ln(2)t), where c is the amount to bring it down to the initial population, something like 1900.

Obviously I'm missing a ln2 somewhere, but I can't locate it.

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