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Math HW help!

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CJHski
Posts: 2384 - Karma: 126
Alright,  I need two different ways to solve this problem and explain my work...

"A number of guests were present at a Mexican fiesta.  There were 65 dishes served.  Every 2 guests shared fajitas, every 3 guests shared a plate of nachos, and every 4 guests shared a bowl of refried beans.  How many guests attended the fiesta?  Show how you know."

Any help would be fantastic!
Jan 25 2010 9:43PM
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prontocuts.com
Posts: 5244 - Karma: 42
I might be retarded but isnt it every 195 people?
Jan 25 2010 9:46PM
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prontocuts.com
Posts: 5244 - Karma: 42
isnt it 195*


im pretty sure im wrong though
Jan 25 2010 9:47PM
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spliff.Life
Posts: 7847 - Karma: 1,544
im sorry i have no idea, my threads because i want to know how to solve it.
Jan 25 2010 9:51PM
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CJHski
Posts: 2384 - Karma: 126
i'm pretty sure you're right, that makes sense i think...
Jan 25 2010 9:57PM
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FerrisBueller
Posts: 8280 - Karma: 5,173
repost.


lol jk that would be impossible
Jan 25 2010 9:58PM
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prontocuts.com
Posts: 5244 - Karma: 42
The problem is worded confusingly.

Is it
2 people eat A, THEN 3 people eat B, THEN 4 people eat C

or is it
2 people eat A B and C, while +1 eats B and +2 eat C
Jan 25 2010 9:59PM
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B4NE1
Posts: 876 - Karma: 16
This one has me beat i thought at first you could use permutations and combinations but you can't really
Jan 25 2010 9:59PM
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CJHski
Posts: 2384 - Karma: 126
no, this is the best way i can explain it:  If you are sitting at a table, 2 people would share the fajitas, 3 people would share one plate and 4 people would share the refried beans.  Every guest eats all three dishes.



Jan 25 2010 10:26PM
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Spillway_East
Posts: 1127 - Karma: 378
85?
Jan 25 2010 10:31PM
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Edew19
Posts: 365 - Karma: 13
its 60 if i read it right.

65=x/2+x/3+x/4  where x is the number of guests.
Jan 25 2010 10:46PM
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MNS
Posts: 5386 - Karma: 3,241


x = amount of people
65 = amount of dishes served

x/2 = amount of fajite dishes served = F
x/3 = amount of nacho dishes served = N
x/4 = amount of bean dishes served = B

F + N + B = 65

x/2 + x/3 + x/4 = 65

13x/12 = 65

x = 60

there were 60 people at the fiesta. let me know if you don't understand, i'll clarify further.

if you wanna check it just go

60/2 = 30 fajita dishes
60/3 = 20 nacho dishes
60/4 = 15 bean dishes

add up the dishes and you get 65
Jan 25 2010 10:52PM
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saucybiscuits
Posts: 2554 - Karma: 173
in the end, they all get diarrhea. They'll be too busy shitting to be worried about math.
Jan 25 2010 10:58PM
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gstaff
Posts: 1017 - Karma: 12
bahahaha  +k
Jan 25 2010 11:02PM
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B-VUR
Posts: 1237 - Karma: 167
If 65 dishes were served, they are mexican...probably thousands.
Jan 25 2010 11:39PM
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1080ski
Posts: 4424 - Karma: 191
Exactly
Jan 25 2010 11:53PM
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KiDCuDi
Posts: 390 - Karma: 13
hahaha <3
Jan 26 2010 12:19AM
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jointman22
Posts: 36 - Karma: 10
alott....cuz there mexicannn!
Jan 26 2010 9:41AM
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