Replying to So i was studying for my calc 3 final...
i was doing one of the old final exams and im not gonna copy the entire problem but here is the hint they gave
"Hint: Nick, “The Nice Guy”, has
tipped you off that you are being “tested”. He suggests that at the
appropriate point in the calculations you might need the substitution u
= y^2xand v = x^2y, which, he kindly points out, is the same as x =
(u^1/3)(v^2/3) and y = (u^2/3)(v^1/3). It’s good for you (and your
kneecaps) that Nick took Calc III years ago and still remembers most of
it."
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