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Physics help...

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slevin_kelevra
Posts: 416 - Karma: 13
I have been working on this for a while and can't figure it out.  Any help would be appreciated

What is the charge Click for larger image inside the Gaussian surface?
Express your answer in terms of Click for larger image(charge density), Click for larger image, and any needed constants.
Click for larger image
Feb 21 2009 6:06PM
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slevin_kelevra
Posts: 416 - Karma: 13
it was supposed to say express in terms of lambda(charge density), and A(Area)
Feb 21 2009 6:07PM
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OhMyBosh
Posts: 5056 - Karma: 171
27
Feb 21 2009 6:14PM
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4mica
Posts: 1017 - Karma: 60
e = mc vagina
Feb 21 2009 6:55PM
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spliff.Life
Posts: 7847 - Karma: 1,549
were not that far yet, thats next month
Feb 21 2009 7:05PM
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Chummer3
Posts: 599 - Karma: 9

so lambda= q/A

the cross sectional area of the plane is pi*r^2

solve for q,  try q=lambda*(pi r^2)

Feb 21 2009 7:15PM
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moonofendor
Posts: 1484 - Karma: 14
so the surgace area intergal equals q over epsilon
$Eda= q/e
E is constant so pull that outta the intergal
so
E$da=q/e
da will be equal to the area
so
Epir^2=q/e
q=L/e
L=q/a
a=pir^2
so q=Lpir^2
so
Epir^2=Lpir^2/e
the pir^2 cancel out
so
E=L/e
or
E=q/pir^2e
or
E=2kq/r^2
Feb 21 2009 7:40PM
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spruitm
Posts: 2221 - Karma: 1,069
GREEN yeaaa
Feb 21 2009 11:12PM
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Scott~
Posts: 2551 - Karma: 49
Pretty sure this is incorrect because the two sides dont cancel out, net flux is positive on both ends so it will actually be twice the area. Also you solved charge as though this was a thin line of charge instead of being an infinite sheet. Which is sigma(charge density) * A.
2 pi r^2 * E = sigma*A/epsilon
You can simplify and manipulate this if youd like, but since you werent actually given anything there isnt a lot you can do.
Feb 21 2009 11:32PM
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NESblowjob
Posts: 1174 - Karma: 41
i think its just charge density over the area of the top of the cylinder
Feb 21 2009 11:38PM
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An10a_Eng
Posts: 2505 - Karma: 26
you = mc fucking faggot
Feb 21 2009 11:40PM
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Hansel.
Posts: 4583 - Karma: 112
haha thank you for making a funny
Feb 21 2009 11:42PM
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slevin_kelevra
Posts: 416 - Karma: 13
thanks +k
 the answer was q=(charge density)*(Area)
Feb 22 2009 5:30PM
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