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November, 2024

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How do I do this?

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Skibumsmith
Posts: 5432 - Karma: 11,823

((x^2y)^(1/3))((xy^2)^(2/3))

big ++++k if you can help

Sep 17 2008 11:49PM
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Skibumsmith
Posts: 5432 - Karma: 11,823

bump

Sep 18 2008 12:03AM
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twsnow22
Posts: 1285 - Karma: 488
wish i could help.... haha free bump tho
Sep 18 2008 12:07AM
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Leo.
Posts: 508 - Karma: 17
((x^2y)^(1/3))((xy^2)^(2/3))
((x^2/3y^1/3)(x^2/3y^4/3)
x^4/3y^5/3

and then to express those wierd exponents, you make the numerator the exponent and and then take root of the bottom number.

so it would be cube root of x to the fourth, cube root of y to the fifth.

so actually the cube root of x to the fourth y to the fifth. all under one radical
Sep 18 2008 12:12AM
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Skibumsmith
Posts: 5432 - Karma: 11,823

YAY! I FIGURED IT OUT!
(x^(4/3))((y^(5/3)) I spent an hour on it. Was it really worth it in the end?

Sep 18 2008 12:58AM
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twsnow22
Posts: 1285 - Karma: 488
good job... haha i still cant figure mine out
Sep 18 2008 1:00AM
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