Homework help. Calculus problem, very hard

What level of Calculus are you in..?

If this is Grade 12 then holy shit.. This is above your level, honestly, atleast when I was back in grade 12 it was.. If you don't understand whats going on in the solution and need it in easier terms, I'd say you're out of luck. The solution pretty much lays out what needs to be done.

But then again this still is a bitch of a question.. and I'm doing second year cacl at university. Just image this question being 3 dimensional.

My best advice would to be skip the questions, you'll never get asked something like this on a test..



*Thats pretty clever in the solution when both sides are multiplied by y.. math nerds understand.

Word I just finished my 4th year of calc which was differential equations, alot of what that was and it was still confusing as fuck. Partially the wording of the question though. Still, that's way above your level if you're still in HS.

im a senior in high school, i took AP calculus AB this year.  i have tried and tried to understand this question, but i have no clue what to do.  its like my final grade, and its worth more than a test, so its bullshit that he gave me one like this.  im thinking about handing in that sheet that says how to do it and being like its way too hard.

You can look at the derivative as this:

The change in rate (distance) over the change in time.

You have to use 'partial derivatives' because you need to use two different derivatives kinda, but not really. Saying you need to use partial derivatives just makes it a little more confusing. The entire wording is really confusing.

Another definition of the derivative is the slope of a curve at one point in time. The same thing as the slope of a curve at a certain point in time is a tangent line. So it's tangent line is going to always be pointing at the ship moving east/horizontally.

It's basically a more complex algebraic equation with a little bit of calculus in it. It's asking you how long does it take ship A (to the north) to travel along the curve and go the same distance as ship B going east in a straight line. Ship A has much further to travel, however it is going at a faster rate, hence why it can catch up to ship B.

I would basically set it up as a complex algebraic equation, something like "30x = 20(arc length integral)y" or whatever with the information they give you. The calculus comes in where you have to use the arc length equation, because you need to integrate the length of the curve. I know that probably isn't the best explanation, but hopefully it helps a little bit.

man i hate differentiation with a passion

im sorry, is that the boat question? dont have time to do it but isnt it pretty straight forward in that the tangent to the curve will be 30. then find the x and y components of motion, determined using the 50m and the speed of the first boat. then antidiffrentiate to get the equation of the curve? maybe im looking at it wrong

Grade 12 calculus us nuts when you have a teacher that hasn't taught in in 20 years (he actually told us that at the start of the unit)

wow i was like im going to help this person out but i read it and i dont have a fucking clue

http://mathproblems.info/prob30s.htm


i clicked solution and got that...

jesus. I thought i was gonna be able to help too. I'm mad good at calculus. but that sucks. good luck

To thread creator "dont bother posting if your going to say do your own homework, because i dont need that at this point" Most people who post looking for help are more along the lines of "fuck school someone do this for me or sell me your paper" i would help but I havent done anything like that since before I graduated.

Im not a rocket scientist.