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Math Help PLZ

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N-John360
Posts: 835 - Karma: 8
Ok this is quite a bit I prolly even put it into 2 dif. posts. This is a test, so try and make sure you get it right.

4/(x-1)-2/(x+3)

x/(x^2+6x+9) + 3/(x^2-9)

5/(y-3) - 7/(3-y)

x/(x+2) - 5x/(x^2-4)

If you help me I will give you a hug...Seriously though, I convinced my teacher to let the test be taken home, and this is the last one, so I need a good grade...and if you help me with all of them (still got like 4 more after this) I might send u money

May 29 2007 5:53PM
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freeskiin1080
Posts: 129 - Karma: 10
hahahah fuck that!!
May 29 2007 5:54PM
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mmmmm...Pie
Posts: 673 - Karma: 15
What are you supposed to be doing to/with those expressions?
May 29 2007 5:57PM
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acc
Posts: 4122 - Karma: 222
if it were homework i'd show you the answers and how to get the answer, but since your lazy ass is trying to get us to give you test answers fuck that. 
May 29 2007 6:03PM
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Xave
Posts: 2672 - Karma: 18
k if you need only to simplify well the first one is:

2(x+7) / (x-1)(x+3)
May 29 2007 6:03PM
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N-John360
Posts: 835 - Karma: 8
Factor first, than I guess you can delete some. Or find the LCD. Somethign like that. EVen if someone just tell me how to do it, I be happy.
May 29 2007 6:04PM
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N-John360
Posts: 835 - Karma: 8
I dont know how to do it...so if u just told me how to do it I wont ask for the answer.
May 29 2007 6:05PM
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Xave
Posts: 2672 - Karma: 18
if im not mistaken second one is :

1 / (x+3)
May 29 2007 6:06PM
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Xave
Posts: 2672 - Karma: 18
do you only need to simplify?
May 29 2007 6:06PM
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N-John360
Posts: 835 - Karma: 8
Jea...well that 1/(x+3) answer was good.

ANd Thanx for the help
May 29 2007 6:12PM
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Xave
Posts: 2672 - Karma: 18
no problem, as for the third one then:

12 / (y-3)

i believe... i dont have all my brain with me right now but ill try to do em all
May 29 2007 6:17PM
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N-John360
Posts: 835 - Karma: 8
Thanks a lot...its some hard stuff, aint it!
May 29 2007 6:20PM
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Xave
Posts: 2672 - Karma: 18
well i wish i could explain but im not really good with english and all the terms i know are in french, so ill try but fuck it if you dont understand:

what you have to do with a adition or substraction of 2 or more terms is to put both terms with the same denominator. to do so, you multiply each term by 1, but you change the 1 with the denominator of the other term, so for instance you have 1/(x+1) + 1/(x) youll have to multiply the first term by x/x and the second one by (x+1)/(x+1) then you factor and develop i guess...

last one's answer is , i think:

x(x+7) / (x+2)(x-2)

or if you develop the denominator:

x(x+7) / (x^2-4)
May 29 2007 6:23PM
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steezyjibber
Posts: 15967 - Karma: 11,026
damn this guy's really helpin you
May 29 2007 6:27PM
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N-John360
Posts: 835 - Karma: 8
Wow...I think I actually get it...Im a try some on my own..really, thanks a lot though!
May 29 2007 6:27PM
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Xave
Posts: 2672 - Karma: 18
haha well i guess that if i ever wanted some math help and came on NS, then i'd appreciate if, among all the "searhc bar nooobz" and "ahh im lazy" there might be someone helpful enough to help me. and in that case im that dude.
oh and i also like maths, and its pretty easy for me.

Glad i've helped.
May 29 2007 6:43PM
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EClay46
Posts: 2499 - Karma: 69
read ur book
how old are u?
like 12 that math is so low level u should be able to do it in ur sleep
May 29 2007 6:43PM
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roaklee
Posts: 1288 - Karma: 90
that is not simplified

2x + 14 / x^2 + 2x -3
May 29 2007 6:45PM
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N-John360
Posts: 835 - Karma: 8
Are you answering your own question? Cause if your asking me, I'm 17, a junior, and I actually get good grades. Even got a 1750 on my SATs, which is somewhere around the 70% percentile. So, its actually not that low level.
May 29 2007 8:12PM
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bigdaddytmac
Posts: 1448 - Karma: 14
Which ones do you still need.
May 29 2007 8:13PM
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bigdaddytmac
Posts: 1448 - Karma: 14
For some reason I just took the time to do those over again. So I can confirm, positively, that all of Splounkalis answers were correct.
May 29 2007 8:25PM
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Xave
Posts: 2672 - Karma: 18
yay me!
May 29 2007 10:02PM
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meggers
Posts: 2094 - Karma: 70
what level math is that? are you trying to solve for x or what?
May 29 2007 10:12PM
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KG_
Posts: 2198 - Karma: 20
who needs math
May 29 2007 10:14PM
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FilmingBitch
Posts: 6463 - Karma: 212
That's expanded you goof.

May 29 2007 10:23PM
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